Question 230 of 298MediumMCQ
If the equation cos4θ+sin4θ+λ=0 has real solutions for θ, then λ lies in the interval: Solutions · 1
Official solution
\[\lambda = -[\cos^4\theta+\sin^4\theta] = -\left[1-2\sin^2\theta\cos^2\theta\right] = \frac12\sin^2(2\theta) - 1\]
Since sin2(2θ)∈[0,1]: 21sin2(2θ)∈[0,21], so:
\[\lambda \in \left[-1,-\frac12\right]\] Answer the question to unlock