The set of all possible values of θ in the interval (0,π) for which the points (1,2) and (sinθ,cosθ) lie on the same side of the line x+y=1 is:
Solutions · 1
Official solution
Let f(x,y)=x+y−1. Since (1,2) and (sinθ,cosθ) lie on the same side, f(1,2)⋅f(sinθ,cosθ)>0:
\[2[\sin\theta+\cos\theta-1]>0 \implies \sin\theta+\cos\theta>1 \implies \sqrt{2}\sin\left(\theta+\tfrac\pi4\right)>1\]
\[\sin\left(\theta+\tfrac\pi4\right) > \frac1{\sqrt{2}} \implies \theta+\frac\pi4 \in \left(\frac\pi4,\frac{3\pi}4\right) \implies \theta\in\left(0,\frac\pi2\right)\]