Question 231 of 298MediumNUMERICAL
The number of distinct solutions of the equation log1/2∣sinx∣=2−log1/2∣cosx∣ in the interval [0,2π] is \_\_\_\_\_\_\_\_\_\_\_
Answer: 8 Solutions · 1
Official solution
\[\log_{1/2}|\sin x\cos x| = 2 \implies |\sin x\cos x| = \frac14 \implies |\sin2x| = \frac12\]
Over [0,2π], sin2x=±21 has 8 solutions. Answer the question to unlock