Official solution
\[\left| z \right| + z = 3 + i\]
\[z = 3 - \left| z \right| + i\]
Let \[3 - \left| z \right| = a \Rightarrow \left| z \right| = \left( {3 - a} \right)\]
\[ \Rightarrow z = a + i \Rightarrow \left| z \right| = \sqrt {{a^2} + 1} \]
\[ \Rightarrow 9 + {a^2} - 6a = {a^2} + 1 \Rightarrow a = {8 \over 6} = {4 \over 3}\]
\[ \Rightarrow \left| z \right| = 3 - {4 \over 3} = {5 \over 3}\]