Let z1 and z2 be any two non-zero complex numbers such that 3∣z1∣=4∣z2∣. If z=2z23z1+3z12z2, then:
Solutions · 1
Official solution
Writing z1=r1eiθ, z2=r2eiφ with 3r1=4r2:
\[z=\frac32\cos(\theta-\varphi)+i\left(2-\frac12\right)\sin(\theta-\varphi)\cdots\]
leads to 23≤∣z∣≤25, which does not match any single stated option exactly, so the answer is (none of the above).