Official solution
\[\tan \theta = - {2 \over 3}\]
Using symmetric from of line
\[P,Q:\left( {2 \pm \sqrt {13} \cos \theta ,3 \pm \sqrt {13} \sin \theta } \right)\]
\[\left( {2 \pm \sqrt {13} .\left( { - {3 \over {\sqrt {13} }}} \right),3 \pm \sqrt {13} \left( {{2 \over {\sqrt {13} }}} \right)} \right)\]
(-1, 5) \& (5, 1)