Two tangents are drawn from the point P(-1, 1) to the circle x2 + y2 - 2x - 6y + 6 = 0.

Question

Two tangents are drawn from the point P(-1, 1) to the circle x2 + y2 - 2x - 6y + 6 = 0. If these tangents touch the circle at points A and B, and if D is a point on the circle such that length of the segments AB and AD are equal, then the area of the triangle ABD is equal to :

Accepted Answer

$$\Delta ABD = {1 \over 2} \times 2 \times 4 = 4$$

Solutions · 1