A circle touches both the y-axis and the line x + y = 0. Then the locus of its center is :
Solutions · 1
Official solution
Let the centre be (h, k)
So, \[\left| h \right| = \left| {{{h + k} \over {\sqrt 2 }}} \right|\]
\[ \Rightarrow 2{h^2} = {h^2} + {k^2} + 2hk\]
Locus will be x2−y2=2xy