The resultant R of two forces acting on a particle is at right angles to one of them, and …

Question

The resultant $R$ of two forces acting on a particle is at right angles to one of them, and its magnitude is one third of the other force. The ratio of the larger force to the smaller one is:

Accepted Answer

Let the forces be $F$ (larger) and $F'$, with $R\perp F'$ and $R=F/3$. Resolving along and perpendicular to $F'$: $F'=F\cos	heta\cdot(	ext{appropriately})$ and $R=F\sin	heta$, leading to $F:F'::3:2\sqrt2$.

Solutions · 1