Question 344 of 379MediumMCQ
For any vector a, the value of ∣a×i^∣2+∣a×j^∣2+∣a×k^∣2 is equal to: Solutions · 1
Official solution
Let a=xi^+yj^+zk^. Then a×i^=zj^−yk^, so ∣a×i^∣2=y2+z2. Similarly ∣a×j^∣2=x2+z2 and ∣a×k^∣2=x2+y2.
\[\text{Sum} = 2(x^2+y^2+z^2)=2|\vec a|^2\] Answer the question to unlock