A unit vector which is perpendicular to the vector 2i^−j^+2k^ and is coplanar with the vectors i^+j^−k^ and 2i^+2j^−k^ is:
Solutions · 1
Official solution
Let the vector be p(i^+j^−k^)+q(2i^+2j^−k^)=(p+2q)i^+(p+2q)j^−(p+q)k^. Perpendicularity to 2i^−j^+2k^ gives:
\[2(p+2q)-(p+2q)-2(p+q)=0 \implies -p=0 \implies p=0\]
So the vector is 2qi^+2qj^−qk^. Making it a unit vector: 4q2+4q2+q2=1⟹q=±31.
Taking q=31: 32i^+32j^−31k^=32i^+2j^−k^