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Question 315 of 379EasyMCQ
If a⃗+b⃗+c⃗=0⃗\vec a+\vec b+\vec c=\vec 0, ∣a⃗∣=3|\vec a|=3, ∣b⃗∣=5|\vec b|=5 and ∣c⃗∣=7|\vec c|=7, then the angle between a⃗\vec a and b⃗\vec b is:
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