If the points of intersection of two distinct conics x2+y2=4b and (a second conic, not preserved in the source) lie on the curve y2=3x2, then 33 times the area of the rectangle formed by the intersection points is \_\_\_\_\_\_\_\_.
Answer: 432
Solutions · 1
Official solution
*(The second conic's equation is missing from the source, so b cannot be independently pinned down --- using only x2+y2=4b and y2=3x2, the intersection points are (±b,±3b), giving rectangle area 43b, so 33×Area=36b; matching the given answer requires b=12. The stated answer is 432.)*