Question 55 of 298MediumMCQ
If the circles (x+1)2+(y+2)2=r2 and x2+y2−4x−4y+4=0 intersect at exactly two distinct points, then: Solutions · 1
Official solution
Second circle: centre (2,2), radius 2. Distance between centres =9+16=5.
Two distinct intersection points: ∣r−2∣<5<r+2⇒r>3 and r<7, so 3<r<7. Answer the question to unlock