Official solution
Let first term = a > 0
Common ratio = r > 0
ar + ar2
+ ar3
= 3 ....(i)
ar5
+ ar6
+ ar7
= 243 ....(ii)
\[ \Rightarrow \] r4(ar + ar2 + ar3) = 243
\[ \Rightarrow \] r4(3) = 243
\[ \Rightarrow \] r = 3 as r > 0
from (i)
3a + 9a + 27a = 3
\[ \Rightarrow \] a = \[{1 \over {13}}\]
\[ \therefore \] S50 = \[{{a\left( {{r^{50}} - 1} \right)} \over {\left( {r - 1} \right)}}\]
= \[{1 \over {26}}\left( {{3^{50}} - 1} \right)\]