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Question 292 of 519MediumMCQ
If 210+29⋅31+28⋅32+⋯+2⋅39+310=S−2112^{10}+2^9\cdot3^1+2^8\cdot3^2+\cdots+2\cdot3^9+3^{10} = S-2^{11}, then SS is equal to:
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