The number of values of \[\alpha\] for which the system of equations :
x + y + z = \[\alpha\]
\[\alpha\]x + 2\[\alpha\]y + 3z = -1
x + 3\[\alpha\]y + 5z = 4
is inconsistent, is
Solutions · 1
Official solution
Δ=1α112α3α135
\[
=1(10α−9α)−1(5α−3)+1(3α2−2α)=α−5α+3+3α2−2α=3α2−6α+3
\]
For inconsistency Δ=0 i.e. α=1
Now check for α=1
\[
x+y+z=1\quad\quad...(i)
\]
x+2y+3z=−1...(ii)x+3y+5z=4...(iii)
By (ii) ×2− (i) ×1x+3y+5z=−3
so equations are inconsistent for α=1