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Joint Entrance Examination
Mathematics
Matrices and Determinants
Question 327
Question 327 of 472
Medium
MCQ
If
A
A
A
is a \[3 \times 3\] non-singular matrix such that
A
A
′
=
A
′
A
AA'=A'A
A
A
′
=
A
′
A
and
B
=
A
−
1
A
′
,
B = {A^{ - 1}}A',
B
=
A
−
1
A
′
,
then
B
B
′
BB'
B
B
′
equals:
A
\[{B^{ - 1}}\]
B
\[\left( {{B^{ - 1}}} \right)'\]
C
\[I+B\]
D
\[I\]
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Official solution
\[BB' = B\left( {{A^{ - 1}}A'} \right)' = B\left( {A'} \right)'\left( {{A^{ - 1}}} \right)' = BA\left( {{A^{ - 1}}} \right)'\] \[ = \left( {{A^{ - 1}}A'} \right)\left( {A\left( {{A^{ - 1}}} \right)'} \right)\] \[ = {A^{ - 1}}A.A'.\left( {{A^{ - 1}}} \right)'\,\,\,\,\,\,\] \[\left\{ {} \right.\] as \[\,\,\,\,\,\,\]
A
A
′
=
A
′
A
AA' = A'A
A
A
′
=
A
′
A
\[\left. \, \right\}\] \[ = I\left( {{A^{ - 1}}A} \right)'\]
=
I
.
I
=
I
2
=
I
= I.I = {I^2} = I
=
I
.
I
=
I
2
=
I
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