Question 314 of 472MediumMCQ
If A2−A+1=0, then the inverse of A is : Solutions · 1
Official solution
Given A2−A+I=0
\[{A^{ - 1}}{A^2} - {A^{ - 1}}A + {A^{ - 1}}.I = {A^{ - 1}}.0\]
(Multiplying \[\,\,\,{A^{ - 1}}\] on both sides)
\[ \Rightarrow A - 1 + {A^{ - 1}} = 0\]
or A−1=1−A Answer the question to unlock