Let \[x=\frac{m}{n}\] (m,n are co-prime natural numbers) be a solution of the equation \[\cos \left(2 \sin ^{-1} x\right)=\frac{1}{9}\] and let \[\alpha, \beta(\alpha >\beta)\] be the roots of the equation mx2−nx−m+n=0. Then th...
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Official solution
Assume sin−1x=θcos(2θ)=91sinθ=±32
as m and n are co-prime natural numbers,
x=32
i.e. m=2,n=3
So, the quadratic equation becomes 2x2−3x+1=0 whose roots are α=1,β=21(1,21) lies on 5x+8y=9