Question 19 of 155MediumMCQ
For α,β,γ=0, if sin−1α+sin−1β+sin−1γ=π and (α+β+γ)(α−γ+β)=3αβ, then γ equals Solutions · 1
Official solution
Let \[\sin ^{-1} \alpha=A, \sin ^{-1} \beta=B, \sin ^{-1} \gamma=C\]
\[A+B+C=π(α+β)2−γ2=3αβα2+β2−γ2=αβ2αβα2+β2−γ2=21⇒cosC=21sinC=γcosC=1−γ2=21γ=23\] Answer the question to unlock