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Question 19 of 155MediumMCQ
For α,β,γ≠0\alpha ,\beta ,\gamma \ne 0, if sin⁡−1α+sin⁡−1β+sin⁡−1γ=π{\sin }^{-1}\alpha +{\sin }^{-1}\beta +{\sin }^{-1}\gamma =\pi and (α+β+γ)(α−γ+β)=3αβ(\alpha +\beta +\gamma )(\alpha -\gamma +\beta )=3\alpha \beta , then γ\gamma equals
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