If ∫0π1+5cosx5cosx(1+cosxcos3x+cos2x+cos3xcos3x)dx=16kπ, then k is equal to \_\_\_\_\_\_.
Answer: 13
Solutions · 1
Official solution
By King's rule (x→π−x), using 1+5cosx5cosx+1+5−cosx5−cosx=1:
\[2I = \int_0^\pi\left(1+\cos x\cos3x+\cos^2x+\cos^3x\cos3x\right)dx\]
By further even/odd symmetry about x=π/2, this reduces (as detailed in the source, using product-to-sum identities) to
\[2I = \frac{13}4\cdot\frac\pi2+\left[\text{a term vanishing at the limits}\right] \implies I = \frac{13\pi}{16}\]
So k=13.