Question 334 of 416MediumMCQ
Let [.] denote the greatest integer function then the value of ∫01.5x[x2]dx is: Solutions · 1
Official solution
∫01.5x[x2]dx=∫01x[x2]dx+∫12x[x2]dx+∫21.5x[x2]dx
=∫01x⋅0dx+∫12x⋅1dx+∫21.5x⋅2dx
=0+[2x2]12+[x2]21.5=21(2−1)+(2.25−2)=21+41=43 Answer the question to unlock