f(x)=∫cosec6xdx
Using the reduction formula In=∫cosecnxdx=−n−1cosecn−2xcotx+n−1n−2In−2:
f(x)=−5cosec4xcotx+54(−3cosec2xcotx+32I2)=−5cosec4xcotx−154cosec2xcotx+158(−cotx)
Expressing cosec2x=1+cot2x and simplifying fully:
f(x)=−5cot5x−32cot3x−cotx+C
It is a polynomial of degree 5 in cotx.