Let f and g be continuous functions on [0,a] such that f(x)=f(a−x) and g(x)+g(a−x)=4, then ∫0af(x)g(x)dx is equal to:
Solutions · 1
Official solution
Let I=∫0af(x)g(x)dx. Using x→a−x:
\[I=\int_0^af(a-x)g(a-x)\,dx=\int_0^af(x)[4-g(x)]\,dx=4\int_0^af(x)dx-I\]
\[\Rightarrow2I=4\int_0^af(x)dx\Rightarrow I=2\int_0^af(x)\,dx\]