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Question 241 of 416MediumMCQ
lim⁡n→∞[nn2+12+nn2+22+nn2+32+⋯+15n]\displaystyle\lim_{n\to\infty}\left[\frac{n}{n^2+1^2}+\frac{n}{n^2+2^2}+\frac{n}{n^2+3^2}+\cdots+\frac1{5n}\right] is equal to :
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