Official solution
f(x) = ax2 + bx + c
f(1) = a + b + c = 3 \[ \Rightarrow \] f (1) = 3
Now f(x + y) = f(x) + f(y) + xy ...(1)
Put x = y = 1 in eqn (1)
f(2) = f(1) + f(1) + 1
= 2f(1) + 1
\[ \Rightarrow \] f(2) = 7
Similarly f(3) = 12
f(4) = 18
\[\sum\limits_{n = 1}^{10} {f(n)} \] = 3 + 7 + 12 + 18 + 25 + 33 + 42 + 52 + 63 + 75 = 330