The equation of the hyperbola whose foci are (-2,0) and (2,0) and eccentricity is 2 is giv…

Question

The equation of the hyperbola whose foci are $(-2,0)$ and $(2,0)$ and eccentricity is $2$ is given by:

Accepted Answer

$ae=2$, $e=2\Rightarrow a=1$. $b^2=a^2(e^2-1)=1(4-1)=3$.

Hyperbola: $\dfrac{x^2}{1}-\dfrac{y^2}{3}=1\Rightarrow3x^2-y^2=3.$

Solutions · 1