Question 50 of 490MediumMCQ
A function y=f(x) satisfies f(x)sin2x+sinx−(1+cos2x)f′(x)=0 with condition f(0)=0. Then, f(2π) is equal to Solutions · 1
Official solution
dxdy−(1+cos2xsin2x)y=sinx=1+cos2xy⋅(1+cos2x)=∫(sinx)dx=−cosx+Cx=0,C=1y(2π)=1 Answer the question to unlock