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Question 49 of 490MediumMCQ
If sin⁡(yx)=log⁡e∣x∣+α2\sin (\frac{y}{x})={\log }_{e}|x|+\frac{\alpha }{2} is the solution of the differential equation xcos⁡(yx)dydx=ycos⁡(yx)+xx\cos (\frac{y}{x})\frac{dy}{dx}=y\cos (\frac{y}{x})+x and y(1)=π3y(1)=\frac{\pi }{3}, then α2{\alpha }^{2} is equal to
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