If sin(xy)=loge∣x∣+2α is the solution of the differential equation xcos(xy)dxdy=ycos(xy)+x and y(1)=3π, then α2 is equal to
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Official solution
Differential equation :-
xcosxydxdy=ycosxy+xcosxy[xdxdy−y]=x
Divide both sides by x2cosxy(x2xdxdy−y)=x1
Let xy=tcost(dxdt)=x1costdt=x1dx
Integrating both sides
sint=ln∣x∣+csinxy=ln∣x∣+c
Using y(1)=3π, we get c=23
So, α=3⇒α2=3