Let f:R→R be a function defined by f(x)=4x+24x and M=∫f(a)f(1−a)xsin4(x(1−x))dx,N=∫f(a)f(1−a)sin4(x(1−x))dx;a=21. If αM=βN,α,β∈N, then the least value of α2+β2 is equal to \_\_\_\_\_\_\_\_\_\_.
Answer: 5
Solutions · 1
Official solution
f(a)+f(1−a)=1M=∫f(a)f(1−a)(1−x)⋅sin4x(1−x)dxM=N−M2M=Nα=2;β=1
Ans. 5