Let S=(−1,∞) and f:S→R be defined as
f(x)=∫−1x(et−1)11(2t−1)5(t−2)7(t−3)12(2t−10)61dt
Let p= Sum of squares of the values of x, where f(x) attains local maxima on S, and q= Sum of the values of x, where f(x) attains local minima on S. Then, the value of p2+2q is \_\_\_\_\_\_\_\_\_.
Answer: 27
Solutions · 1
Official solution
f′(x)=(ex−1)11(2x−1)5(x−2)7(x−3)12(2x−10)61
Local minima at x=21,x=5
Local maxima at x=0,x=2∴p=0+4=4,q=21+5=211
Then p2+2q=16+11=27