The point represented by 2 + i in the Argand plane moves 1 unit eastwards, then 2 units northwards and finally from there \[2\sqrt 2 \] units in the south-westwardsdirection. Then its new position in the Argand plane is at the point represented by :
Solutions · 1
Official solution
Here,
z - (3 + 3i) = \[2\sqrt 2 \] (cos(-135o) + i sin (- 135o))
= \[2\sqrt 2 \] (- \[{1 \over {\sqrt 2 }}\] - 2i)
=−2−2i⇒z = 3 + 3 i−2-\[ 2 i = 1 + i
Note :
Polar form of a complex number :
z = r (cos\]\theta + i sinθ)
Here r = modulus of z andθ