Sachin and Rahul attempted to solve a quadratic equation.

Question

Sachin and Rahul attempted to solve a quadratic equation. Sachin made a mistake in writing down the constant term and got roots $(4,3)$. Rahul made a mistake in writing the coefficient of $x$ and got roots $(3,2)$. The correct roots of the equation are:

Accepted Answer

Sachin's sum of roots is correct: $4+3=7=-\dfrac ba$. Rahul's product of roots is correct: $3	imes2=6=\dfrac ca$.

Correct equation: $x^2-7x+6=0 \implies (x-6)(x-1)=0$, roots $6,1.$

Solutions · 1