Let a a_10, f(x)=ax^2+bx+c, g(x)=a_1x^2+b_1x+c_1, and p(x)=f(x)-g(x).

Question

Let $a
e a_1
e0$, $f(x)=ax^2+bx+c$, $g(x)=a_1x^2+b_1x+c_1$, and $p(x)=f(x)-g(x)$. If $p(x)=0$ only for $x=-1$ and $p(-2)=2$, then the value of $p(2)$ is:

Accepted Answer

$p(x)=(a-a_1)(x+1)^2$ (double root at $-1$). $p(-2)=(a-a_1)=2$.

$$p(2)=(a-a_1)(2+1)^2=2\times9=18.$$

Solutions · 1