A equation of a plane parallel to the plane x−2y+2z−5=0 and at a unit distance from the origin is :
Solutions · 1
Official solution
Given equation of a plane is
x−2y+2z−5=0
So, Equation of parallel plane is given by
x−2y+2z+d=0
Now, it is given that distance from origin to the parallel planes is 1.
\[\therefore\] \[\left| {{d \over {\sqrt {{1^2} + {2^2} + {2^3}} }}} \right| = 1 \Rightarrow d = \pm 3\]
So equation of required plane
\[x - 2y + 2z \pm 3 = 0\]