questionr
Early access
Exams
Joint Entrance Examination
Mathematics
3D Geometry
Question 458
Question 458 of 521
Easy
MCQ
The projections of a vector on the three coordinate axis are
6
,
−
3
,
2
6,-3,2
6
,
−
3
,
2
respectively. The direction cosines of the vector are :
A
\[{6 \over 5},{{ - 3} \over 5},{2 \over 5}\]
B
\[{6 \over 7 },{{ - 3} \over 7},{2 \over 7}\]
C
\[{- 6 \over 7 },{{ - 3} \over 7},{2 \over 7}\]
D
\[6, -3, 2\]
Check answer
Press A-D to select · Enter to check
Solutions · 1
Post your solution
Official solution
Let \[P\left( {{x_1},{y_1},{z_1}} \right)\] and \[Q\left( {{x_2},{y_2},{z_2}} \right)\] be the initial and final points of the vector whose projections on the three coordinates axes are
6
,
−
3
,
2
{6, - 3,2}
6
,
−
3
,
2
then \[{x_2} - {x_1}, = 6;\,\,{y_2} - {y_1} = - 3;\,\,{z_2} - {z_1} = 2\] So that directions ratios of \[\overrightarrow {PQ} \] are
6
,
−
3
,
2
{6, - 3,2}
6
,
−
3
,
2
\[\therefore\] Direction cosines of \[\overrightarrow {PQ} \] are \[{6 \over {\sqrt {{6^2} + {{\left( { - 3} \right)}^2} + {2^2}} }},{{ - 3} \over {\sqrt {{6^2} + {{\left( { - 3} \right)}^2} + {2^2}} }},\] \[\,\,\,\,\,\,\,\,\] \[{2 \over {\sqrt {{6^2} + {{\left( { - 3} \right)}^2} + {2^2}} }} = {6 \over 7},{{ - 3} \over 7},{2 \over 7}\]
Answer the question to unlock
Previous
Next