Question 372 of 379EasyMCQ
If a,b,c are vectors such that a+b+c=0 and ∣a∣=7, ∣b∣=5, ∣c∣=3, then the angle between vectors b and c is: Solutions · 1
Official solution
b+c=−a⟹∣b+c∣2=∣a∣2⟹25+9+2b⋅c=49⟹2(5)(3)cosθ=15
\[\cos\theta=\frac12 \implies \theta=60^{\circ}\] Answer the question to unlock