Question 35 of 379MediumMCQ
Let a→=3i^−j^+2k^,b→←=a→×(i^−2k^) and c→=b→×k^. Then the projection of c→−2j^ on a is : Solutions · 1
Official solution
b→=a→×(i^−3k^)=∣i^j^k^3−1210−2∣=2i^+8j^+k^c→=b→×k^=8i^−2j^c→−2j^=8i^−4j^(i^−2j^)a(c→−2j^)⋅a^=14⟨8,−4,0⟩⋅⟨3,−1,2⟩=1428=214 Answer the question to unlock