Question 340 of 379EasyMCQ
If C is the mid point of AB and P is any point outside AB, then: Solutions · 1
Official solution
PA+AC+CP=0 \ldots (i), PB+BC+CP=0 \ldots (ii). Adding, and using AC=−BC (C is midpoint):
\[\overrightarrow{PA}+\overrightarrow{PB}+2\overrightarrow{CP}=\vec0 \implies \overrightarrow{PA}+\overrightarrow{PB}=2\overrightarrow{PC}\] Answer the question to unlock