If (a×b)×c=a×(b×c) where a,b and c are any three vectors such that a⋅b=0, b⋅c=0, then a and c are:
Solutions · 1
Official solution
\[(\vec a\cdot\vec c)\vec b-(\vec b\cdot\vec c)\vec a = (\vec a\cdot\vec c)\vec b-(\vec a\cdot\vec b)\vec c \implies (\vec a\cdot\vec b)\vec c=(\vec b\cdot\vec c)\vec a\]
Since a⋅b=0 and b⋅c=0, this gives c as a scalar multiple of a, i.e. a∥c.