If a and b are non-collinear vectors, then the value of α for which the vectors u=(α−2)a+b and v=(2+3α)a−3b are collinear is:
Solutions · 1
Official solution
For collinearity, ku+v=0 for some scalar k: [k(α−2)+2+3α]a+(k−3)b=0.
Since a,b are non-collinear (independent): k−3=0⟹k=3, and
\[3(\alpha-2)+2+3\alpha=0 \implies 6\alpha-4=0 \implies \alpha=\frac23\]