Question 301 of 379EasyMCQ
If ∣a∣=2, ∣b∣=3 and ∣2a−b∣=5, then ∣2a+b∣ equals: Solutions · 1
Official solution
∣2a−b∣2=4∣a∣2+∣b∣2−4a⋅b=25⟹16+9−4a⋅b=25⟹a⋅b=0
\[|2\vec a+\vec b|^2=4|\vec a|^2+|\vec b|^2+4\vec a\cdot\vec b=16+9+0=25 \implies |2\vec a+\vec b|=5\] Answer the question to unlock