If the volume of the parallelepiped formed by i^+λj^+k^, j^+λk^, λi^+k^ is minimum, then λ is:
Solutions · 1
Official solution
\[V = \begin{vmatrix}1&\lambda&1\\0&1&\lambda\\ \lambda&0&1\end{vmatrix} = |\lambda^3-\lambda+1|\]
Let f(λ)=λ3−λ+1. f′(λ)=3λ2−1=0⇒λ=±31. f′′(λ)=6λ; f′′(31)>0, so λ=31 gives a local minimum of f (and hence of ∣f∣ near that point, per the source).