If a→ is a nonzero vector such that its projections on the vectors 2i^−j^+2k^,i^+2j^−2k^ and k^ are equal, then a unit vector along a→ is :
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Official solution
Projection of a on v=∣v∣a⋅v−⇒3a⋅(2i^−j^+2k^)=1a⋅k^=3a⋅(i^+2j^−2k^)⇒a⋅(2i^−j^−k^)=0a⋅(i^+2j^−5k^)=0⇒a⊥(2i^−j^−k^)(i^+2j^−5k^)⇒a∥(2i^−j^−k^)×(i^+2j^−5k^)⇒a=±k∣i^−j^k^2−1−112−5∣=±k(7i^+9j^−5k^)⇒1551(7i^+9j^+5k^)