Question 271 of 379MediumNUMERICAL
If a=2i^+j^+2k^, then ∣i^×(a×i^)∣2+∣j^×(a×j^)∣2+∣k^×(a×k^)∣2 equals \_\_\_\_\_\_\_\_.
Answer: 18 Solutions · 1
Official solution
i^×(a×i^)=(i^⋅i^)a−(i^⋅a)i^=a−2i^=j^+2k^; similarly for j^,k^: j^×(a×j^)=2i^+2k^, k^×(a×k^)=2i^+j^.
\[|\hat j+2\hat k|^2+|2\hat i+2\hat k|^2+|2\hat i+\hat j|^2 = 5+8+5=18\] Answer the question to unlock