Question 261 of 379MediumNUMERICAL
Let a,b,c satisfy ∣a∣=3, ∣b∣=5, b⋅c=10, angle between b,c is 3π, and a⊥(b×c). Then ∣a×(b×c)∣ is \_\_\_\_\_\_\_.
Answer: 30 Solutions · 1
Official solution
b⋅c=∣b∣∣c∣cos3π=10⇒5∣c∣(21)=10⇒∣c∣=4.
\[|\vec a\times(\vec b\times\vec c)| = |\vec a||\vec b\times\vec c|\sin90^{\circ} = \sqrt{3}\cdot|\vec b||\vec c|\sin\frac\pi3 = \sqrt{3}\cdot5\cdot4\cdot\frac{\sqrt{3}}2 = 30\] Answer the question to unlock