Question 225 of 379MediumNUMERICAL
Let a=i^+2j^−k^, b=i^−j^, c=i^−j^−k^. If r×a=c×a and r⋅b=0, then r⋅a is \_\_\_\_\_.
Answer: 12 Solutions · 1
Official solution
(r−c)×a=0⇒r=λa+c.
r⋅b=0: λ(a⋅b)+c⋅b=0. a⋅b=1−2=−1, c⋅b=1+1=2: −λ+2=0⇒λ=2.
r=2a+c. r⋅a=2∣a∣2+a⋅c=2(6)+(1−2+1)=12+0=12. Answer the question to unlock