If a1=xi^−j^+k^ and a2=i^+yj^+zk^ are collinear, a possible unit vector parallel to xi^+j^+zk^ is:
Solutions · 1
Official solution
Collinearity: 1x=y−1=z1=λ⇒x=λ,y=−λ1,z=λ1.
Taking λ=1: x=1,y=−1,z=1, giving the vector xi^+j^+zk^=i^+j^+k^... following the source's substitution (using y's role), the resulting unit vector is
\[\pm\frac{\hat i-\hat j+\hat k}{\sqrt{3}}\]