Let a,b,c be coterminous edges of a parallelepiped of volume V. The volume of the parallelepiped with coterminous edges a, b+c, a+2b+3c is:
Solutions · 1
Official solution
Using the determinant of coefficients relative to {a,b,c}:
\[\begin{vmatrix}1&0&0\\0&1&1\\1&2&3\end{vmatrix} = 1(3-2) = 1\]
So the new volume =1×[abc]=V.